|

Question: Consider a space shuttle that carries life support material from earth to moon. A straight motion with 384000 km is the closest distance between earth and moon -Free Course Hero Question Answer.

Question Description:

Consider a space shuttle that carries life support material from earth to moon. A straight motion with 384000 km is the closest distance between earth and moon. Assuming the shuttle’s acceleration is  20.7 m/s2  for the first time interval 14.6 min of the trip, then travels with a constant velocity until the last time interval 14.6 min, when it accelerates at − 20.7 m/s2 , just coming to rest as it reaches the moon.

a- Find the maximum velocity reached?

b- Which part of the total distance is traveled at constant velocity?

c- How much time is needed for the whole trip?

Free Course Hero Answer

Course Hero Answer & Explanation:

a)18133.2 m/s

b) 368115316.8 m

c) 367.54 minutes.

Image transcription text

Distance = 384 000 Km = 3. 84x 10. For first 14. 6 minutes = 14. 6 x 60 = 876 sec the acceleration = 20-7 m/s a ) V = u + at V = 0 + 20.7 x 876 V = 18 1 3 3 - 2 m / s 3 ) Distance travelled during acceleration d , = ut + I at ? 0 + 1 x 20. 7 ( 87 6 ) d = 7 9 4 2 3 4 1 . 6 m Distance travelled during deeclesation d2= ut - I - at 2 181 3 3 .2 ( 876 ) - 2 ( 20 . 7 ) ( 87 6 ) 2 7 9 4 2 3 4 1 - 6 m Distance tracked at constant velocity = 3 8 4 0 0 0 0 0 0 - 794 2 3 4 1 . 6 - 79 4 2341.6 E 3 6 8 1 1 5 3 1 6 . 8 m C 

Image transcription text

c) Time taken to cover the distance at constant speed of 1813 3 - 2 is t = 3 6 8 1 1 5 3 1 6 . 8 m 1 8 1 3 3 . 2 m / s 1 = 2 0 3 0 0 . 6263 Seconds 3 3 8- 34 min Total time taken = 3 3 8 : 34 + 14.6 + (4. 6 367. 54 min

Similar Posts